Evaluate XPATH in Java

This is straight forward and I think better than iterating through the document tree. There is a evaluate method available in XPATH interface.

Here is a sample code for it:

import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpressionException;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;


public class ApplyXPATH {

    public static void main(String[] args) {
        XPath xpath = XPathFactory.newInstance().newXPath();
        InputSource inputSource = new InputSource("XMLs/MultiNode.xml");
        String expression = "//node/data";
        NodeList outPut=null;
        try {
            outPut = (NodeList) xpath.evaluate(expression, inputSource, XPathConstants.NODESET);
        } catch (XPathExpressionException e) {
            e.printStackTrace();
        }
        for(int i=0; i<outPut.getLength();i++) {
            System.out.println(outPut.item(i).getFirstChild().getNodeValue());
        }
    }
}

Sample Input:

<root>
    <node>
        <data>123</data>
        <data>456</data>
        <junk>abc</junk>
    </node>
    <junknode>
        <junk>def</junk>
    </junknode>
    <node>
        <data>789</data>
        <junk>ghi</junk>
        <data>012</data>
    </node>
</root> 

Sample Output:

123
456
789
012 

Here I am just printing the node values but you can easily create a new XML document and append this nodelist to it.

PS: if you change the expression to //node/data/text() then to access the value you just need to do outPut.item(i).getNodeValue()